Bug 1737252 - [devtools] Escaping back tick signs. r=nchevobbe, a=RyanVM

devtools/client/shared/curl.js

@@ -8,6 +8,7 @@
  * Copyright (C) 2008, 2009 Anthony Ricaud <rik@webkit.org>
  * Copyright (C) 2011 Google Inc. All rights reserved.
  * Copyright (C) 2009 Mozilla Foundation. All rights reserved.
+ * Copyright (C) 2022 Moonchild Productions. All rights reserved.
  *
  * Redistribution and use in source and binary forms, with or without
  * modification, are permitted provided that the following conditions
@@ -400,9 +401,15 @@ const CurlUtils = {
    */
   escapeStringWin: function (str) {
     /* 
-       Replace dollar sign because of commands (e.g $(cmd.exe)) in
-       powershell when using double quotes.
-       Useful details http://www.rlmueller.net/PowerShellEscape.htm
+       Replace the backtick character ` with `` in order to escape it.
+       The backtick character is an escape character in PowerShell and
+       can, among other things, be used to disable the effect of some
+       of the other escapes created below.
+
+       Replace dollar sign because of commands in powershell when using
+       double quotes. e.g $(calc.exe).
+       
+       Also see http://www.rlmueller.net/PowerShellEscape.htm for details.
 
        Replace quote by double quote (but not by \") because it is
        recognized by both cmd.exe and MS Crt arguments parser.
@@ -416,13 +423,15 @@ const CurlUtils = {
        MS Crt arguments parser won't collapse them.
 
        Replace new line outside of quotes since cmd.exe doesn't let
-       to do it inside.
+       us do it inside.
     */
-    return "\"" + str.replace(/\$/g, "`$")
-                     .replace(/"/g, "\"\"")
-                     .replace(/%/g, "\"%\"")
-                     .replace(/\\/g, "\\\\")
-                     .replace(/[\r\n]+/g, "\"^$&\"") + "\"";
+    return "\"" + 
+      str.replaceAll("`", "``")
+         .replaceAll("$", "`$")
+         .replaceAll('"', '""')
+         .replaceAll("%", '"%"')
+         .replace(/\\/g, "\\\\")
+         .replace(/[\r\n]+/g, "\"^$&\"") + "\"";
   }
 };